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Mathematics 8 Online
OpenStudy (anonymous):

Can someone help me with the following integral:

OpenStudy (anonymous):

OpenStudy (anonymous):

int:sin(x)^3cos(x) use u substitution let u = sinx du =cosxdx new integral: int:u^3du =(1/4)u^4+C plug back in sinx for u sin^4(x)/4+c

OpenStudy (anonymous):

that's what it looks like in better symbol form when finished. open for any questions

OpenStudy (anonymous):

Thank you very much. I tryied so hard and I could not find the answer. Thank you so much

OpenStudy (anonymous):

Your welcome, glad to help.

OpenStudy (anonymous):

any others?

OpenStudy (anonymous):

Yeah I have problem with three. well now two

OpenStudy (anonymous):

can you help me with them?

OpenStudy (anonymous):

Im just learning how to integrate

OpenStudy (anonymous):

I can try, aha but i won't promise! ;P

OpenStudy (anonymous):

in other words i'll do my best

OpenStudy (anonymous):

let me post the other two

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

Can you see it?

OpenStudy (anonymous):

no....

OpenStudy (anonymous):

Ok let me try again

OpenStudy (anonymous):

OpenStudy (anonymous):

what about now?

OpenStudy (anonymous):

yeah i can see it, okay this one is a little more difficult . you have to use trigonometric identities

OpenStudy (anonymous):

Do you think you can solve it?

OpenStudy (anonymous):

let me think for a sec

OpenStudy (anonymous):

ok :)

OpenStudy (anonymous):

that's kind of a difficult one, however if you want to see all the steps.. i won't do them personally but here is something you can refer to

OpenStudy (anonymous):

i guess it doesn't take you to the answer i put in, so just enter cos^7(x)

OpenStudy (anonymous):

you can click see steps for indefinite integral.

OpenStudy (anonymous):

are you sure that there isn't a sin, in your problem? that would make it so much easier

OpenStudy (anonymous):

Im learning calculus so it will be awsome if you show me how to integrate with sin as well.

OpenStudy (anonymous):

well i can do my best, i wasn't really able to help with the last one really though, if the integrand has sin and cos in it, that is easier

OpenStudy (anonymous):

I think I found a way to solve it. I need to try a little bit harder. Any question I will let you know my friend

OpenStudy (anonymous):

sounds good! good luck

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