Question

solve the inequality :
x^3-2X^2-X+2 less than or equal to 0

Answer 1

\[x^3-2x^2-x+2 \le 0\]\[x^2(x-2)-(x-2) \le 0\]\[(x-2)(x^2-1) \le 0\]

x-2=0 and x^2-1=0
x=2 x^2=1
x= +/- 1

Sub these values into the original equation to determine which way the inequality goes.

Then you should get \[x \le -1\]\[ 1\le x \le 2\]