How long will it take for $2000 to double if it is invested at 6.25% interest compounded continuously? can some show me how to set this problem into this equation A=Pe^rt, please!
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OpenStudy (mertsj):
\[4000=2000e ^{.0625t}\]
OpenStudy (mertsj):
\[2=e ^{.0625t}\]
OpenStudy (mertsj):
\[\ln 2=.0625t(\ln e)\]
OpenStudy (mertsj):
\[\frac{\ln2}{.0625}=t\]
OpenStudy (mertsj):
\[11.09 yrs = t\]
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OpenStudy (anonymous):
can you please give me a crash course on what you did, Please...
OpenStudy (mertsj):
Did you understand how the values were substituted into the equation?
OpenStudy (anonymous):
no i didnt
OpenStudy (mertsj):
A is the amount which was determined to be $4000 because the problem asked how long it would take a $2000 investment to double.
OpenStudy (mertsj):
If $2000 doubles, it will then be $4000 would you agree?
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OpenStudy (mertsj):
So the problem is really asking "how long will it take $2000 to turn into $4000"
OpenStudy (anonymous):
what does the e stand for?
OpenStudy (mertsj):
The e is a frequently used mathematical constant. It doesn't stand for anything. It is sort of like pi. Just a commonly used constant. It is part of the formula just like pi is when you write
OpenStudy (mertsj):
\[A=\pi r^2\]
OpenStudy (mertsj):
You don't replace pi with anything and you don't replace e with anything.
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OpenStudy (anonymous):
can you help me figure out another problem but let me do it and maybe you can coach me.
OpenStudy (mertsj):
It's numerical value (if you must know) is 2.718281828...
OpenStudy (mertsj):
ok
OpenStudy (mertsj):
Lay it on me.
OpenStudy (anonymous):
What rate of interest compounded continuously is needed for an investment of $500 to grow to $900 in 10 years?
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OpenStudy (mertsj):
What is A?
OpenStudy (anonymous):
900
OpenStudy (mertsj):
What is P?
OpenStudy (anonymous):
500
OpenStudy (mertsj):
What is t?
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OpenStudy (anonymous):
10
OpenStudy (mertsj):
What are you trying to find?
OpenStudy (anonymous):
the rate of interest
OpenStudy (mertsj):
Yes. r
OpenStudy (mertsj):
So plug everything in.
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OpenStudy (anonymous):
900=500e^r10
OpenStudy (mertsj):
\[900=500e ^{10r}\]
OpenStudy (mertsj):
Divide both sides by 500
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
In1.8=e^10r
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OpenStudy (mertsj):
\[1.8=e ^{10r}\]
OpenStudy (mertsj):
Now when you take the natural log of both sides it should look like this:
\[\ln 1.8=\ln e ^{10r}\]
OpenStudy (anonymous):
ok
OpenStudy (mertsj):
Now bring the exponent down using the third law of logs and get this
OpenStudy (mertsj):
\[\ln 1.8=10r \ln e\]
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OpenStudy (mertsj):
But of course ln e = 1 so we have:
OpenStudy (mertsj):
\[\ln 1.8=10r\]
OpenStudy (mertsj):
So just divide both sides by 10 and you are done
OpenStudy (anonymous):
0.18=r
OpenStudy (mertsj):
\[\frac{\ln 1.8}{10}=r=.05878=5.88 %\]
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OpenStudy (mertsj):
Did you take the natural log of 1.8 before you divided by 10?
OpenStudy (anonymous):
no
OpenStudy (mertsj):
Do you now how to do that?
OpenStudy (anonymous):
no
OpenStudy (mertsj):
You do understand that it says ln 1.8 divided by 10?
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OpenStudy (mertsj):
Do you have a scientific calculator?
OpenStudy (anonymous):
yes
OpenStudy (mertsj):
Can you find the ln button?
OpenStudy (mertsj):
It's probably right next to the log button
OpenStudy (anonymous):
yes i just pressed it and got the same as you did do i now dive that by 10
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OpenStudy (mertsj):
Yes
OpenStudy (mertsj):
Now multiply by 100 to change it to percent.
OpenStudy (anonymous):
got it you just answered my question!! thank you so much Mertsj
OpenStudy (mertsj):
You're welcome and good luck. Isn't learning fun???!!!
OpenStudy (anonymous):
yeah your the best!!!!!
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