Question

can someone help please?

Answer 1

better to just ask a question

Answer 2

can someone help me im stumped on this problem i need help please. A computer is infected with the Sasser virus. Assume that it infects 20 other computers within 5 minutes; and that these PCs and servers each infect 20 more machines within another five minutes, etc. How long until 100 million computers are infected?

Answer 3

the computer's screwed

Answer 4

does it have something to do with powers turing? i suck at these types of questions

Answer 5

logs and exponential functions

Answer 6

it's not my thing either...

Answer 7

\[20^{\frac{t}{5}}=100,000,000\]

Answer 8

I almost came up with that!

Answer 9

oh crap that is wrong. that will not do it

Answer 10

plus one in there right?

Answer 11

because i was not counting the ones already infected

Answer 12

\[20^{1+\frac t5}=10000000\]

Answer 13

no?

Answer 14

gotta sum this sucker up, let me see if i remember.

Answer 15

10^8=20^5t

Answer 16

should be
\[\frac{t}{5}\] or maybe what turing said, but we are neglecting the ones infected along the way

Answer 17

\[20+20^2+20^3+...\]

Answer 18

so lets try
\[\sum_{k=1}^n20^k=10^8\]
\[\frac{20^{n+1}-1}{19}=10^8\]
\[20^{n+1}=19\times 10^8\]
\[(n+1)=\frac{\ln(19\times 10^8)}{\ln(20)}\]

Answer 19

can you please explain what you have?

Answer 20

i was summing the geomtric series
\[20 + 20^2+20^3+...\] and seeing when it would equal 10^8

Answer 21

i get approximately 7, so that means around 35 minutes

Answer 22

so it would 20^7 how can i log it

Answer 23

I got it 20^5t=10^8

Answer 24

20^0t=120/4

Answer 25

t=30