There is apotential difference of 150 volts between two conductors of a power line .A charge of 600 C is carried from one conductor to the other.What work is required? If the time necessary to transport the charge is 1.25 s how much power is used?

Question

jamesj · Answer

$$ Work = q \Delta V $$ Hence it's straight forward to calculate the work done here, as $ q = 600 \ C $ and $ \Delta V = 150 \ V $.

Power = Work/Time, so now you can also calculate power.