Question

Given the triangle below, what is cot∡B?

Answer 1

Please give the triangle :D

Answer 2

A) square root of 33 over 7

B) 7 times square root of 33 over 33

C) 4 times square root of 33 over 33

D) square root of 33 over 4

Answer 3

It is D) Square root of 33 over 4.

Answer 4

okay I have one more question!

Answer 5

Shoot

Answer 6

what is the value of x?

Answer 7

Can't see x in the given figure.

Answer 8

this is a multi-step problem.
First, you need to know that cot B = 1/tan B
so if we can find tan B, we flip it to get cot B
tan B = opposite/adjacent
opposite=4
adjacent= ?
to find adjacent we use pythagoras: a^2 + b^2 = c^2
here a=? , b=4, c=7, so: a^2 + 16= 49 and a^2= 49-16= 33
so a= sqrt(33)

putting it together: tan B= 4/sqrt(33), and cot B= sqrt(33)/4

Answer 9

sec∠C - cot∠A = 3x

A) fraction 7 minus square root of 13 over 18

B) square root of 13 over 3

C) fraction square root of 13 over 3

D) fraction 6 minus square root of 13 over 7

Answer 10

First, can you find the length of side AB?