Alan leaves Los Angeles at 8:00 a.m. to drive to San Francisco, 400 away. He travels at a steady 45.0 . Beth leaves Los Angeles at 9:00 a.m. and drives a steady 57.0. How long does the first have to wait for the second?

Question

Alan leaves Los Angeles at 8:00 a.m. to drive to San Francisco, 400  away. He travels at a steady 45.0 . Beth leaves Los Angeles at 9:00 a.m. and drives a steady 57.0. How long does the first have to wait for the second?

anonymous · Answer

Assuming that Beth gets there first

turingtest · Answer

you don't have to assume anything
velocity is distance over time:$$v=\frac dt$$so time can be found from distance and velocity$$t=\frac dv$$for the Alan the time of travel is is$$t_A=\frac d{v_A}$$and for Beth the time taken is$$t_B=\frac d{v_B}+1$$(the +1 is for the extra hour she waits to depart)

all we need is the difference of the times$$\Delta t=t_A-t_B$$and that will tell us how long they waited.

anonymous · Answer

So Beth waited 53 minutes... Thanks for the help :)