Question

graph the fuction f(x)= 1/x+8

Answer 1

when x goes to zero y approaches 8

Answer 2

yea i am trying to determine what the graph would look like

Answer 3

But I am thy Master Chief?

http://www.wolframalpha.com/input/?i=y%3D.5x%2B8

Answer 4

it's 1/x not (1/2)x there chief

Answer 5

well it 1/(x+8)

Answer 6

Preposterous! How could I have made such a delinquent mistake?

http://www.wolframalpha.com/input/?i=y%3D%281%2Fx%29%2B8

Answer 7

but (x-8) is different from x+8 when graphing

Answer 8

you know anyone can type numbers in to wolfram

Answer 9

(x+8) oops

Answer 10

i'm talking to chief

Answer 11

yea i want to know how to graph the thing

Answer 12

Well of course, although I could rule the Earth if it was off limits to everyone but me...

Answer 13

i can go to a graphing calculator and not come here but it doesnt teach me how to graph it

Answer 14

i disagree chief. conversation over.

Answer 15

So i assume that I would substitute random numbers for X to graph it?

Answer 16

Make a table and input numbers for x like 0, and then see what comes out as y. Keep getting numbers until you can make a decent graph.

Answer 17

so if x= 0 y would = 1/8

Answer 18

Disagree with what? Obviously, no s**t anyone can use it! I linked a page to the graph, to make things easier even though I misunderstood the question.

Answer 19

Umm, Well, you put 0 in for x. This cancels out the numerator of 1 above it. The answer would be 8.

Answer 20

Because 1 divided 0 is nothing, 0.

Answer 21

1/(x+8)

Answer 22

i cant figure out how to put the one over both in here

Answer 23

in the original problem there is no parenthesis

Answer 24

Oh, that's a different story. Yes, it would com eout as \[1/8\]

Answer 25

because x+8 and (x+8) would be different shifts when graphing wouldnt it?

Answer 26

Yes, the solution graph would differ.

Answer 27

one would shift the graph up and one would shift the graph left

Answer 28

so i am assuming there would be a hole in my graph at -8

Answer 29

because -8+8 = 0

Answer 30

Sorry, it appears so. I have not taken this but look:

http://www.wolframalpha.com/input/?i=y%3D1%2F%28x%2B8%29%2C+y%3D%281%2Fx%29%2B8

Answer 31

I entered the two equations.

Answer 32

the first one is correct. Thats where I was confused

Answer 33

because at x=-9

Answer 34

Yes, it does move the graph to the right if you seclude the +8

Answer 35

the equation would result in a negative

Answer 36

hence a verticle asymtope at -8

Answer 37

x can never be -8 )

Answer 38

I would love to answer your question here but I really don't know. I'm in eighth grade and enrolled in Algebra 2. Sorry!

Answer 39

you did great, and you helped me answer a college calculus question

Answer 40

just remember that the denominator can never = 0 so if it does you have a hole

Answer 41

hence for 1/(-8+8)

Answer 42

=1/0

Answer 43

Oh wow, Thank you!

And yes, because you can't have, for instance, 4 slices of nothing, right?

Answer 44

the value doesnt exist

Answer 45

Like, 4/0

Answer 46

so in your graph that spot would be left open

Answer 47

it doesnt exist

Answer 48

Yes, I know what you mean. It's like trying to have one piece of nothing. That doesn't exist!

Answer 49

I understand now.

Answer 50

so in this case we have an asymptope which means we can get closer and closer to 8

Answer 51

Yup, I get it now thanks!

Answer 52

such as 7.999

Answer 53

so the graph goes up and down at 8 infinitely

Answer 54

I think so.