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Mathematics 14 Online
OpenStudy (anonymous):

How do you integrate (sin(x))^3 ?

OpenStudy (anonymous):

I already looked at Wolfram and I don't want to use the reduction formula

OpenStudy (bahrom7893):

Sin*(Sin^2(x))

OpenStudy (bahrom7893):

Then: Sin*(1-Cos^2(x))

OpenStudy (bahrom7893):

That leads to Sin - Sin*Cos^2 split it into two integrals

OpenStudy (bahrom7893):

first one is easy, second one - integration by parts, then you go through the loop again

OpenStudy (bahrom7893):

I say reduction formula I think it's 1/2 something... is much easier

OpenStudy (anonymous):

ok I see what you want to do

OpenStudy (anonymous):

I've never been taught that reduction formula so I'd rather not use it yet

OpenStudy (bahrom7893):

remember that? Then at the end you get something like Int(Sin*Cos^2) = __________ - Int(Sin*Cos^2), then u add Int(Sin*Cos^2) to both sides and divide by two or whatever..

OpenStudy (anonymous):

yeah that makes sense I'll try it using your strategy

OpenStudy (anonymous):

I ended up using subsitution for the second part because it seemed easier I got (((cos(x))^3)/3) - cos(x) Thanks again for your help!

OpenStudy (turingtest):

yes, subbing for the second part is way easier, it's practically udu already because it is cos^n(x)*(-sinx)

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