Question

a car is traveling in a straight line and decelerating at a constant rate. after 3.2 seconds it has traveled 88m and slowed to a speed of 27 m/s what is the initial speed i got 52 m/s

Answer 1

\[v^2-2as=u^2\]

Answer 2

what does s and u stand for?

Answer 3

Put
\[a=\frac{v-u}{t}\]

Answer 4

s distance
u initial velocity

Answer 5

and the plug a back into the equation that is what i did but im not sure if my math is right

Answer 6

other people had like 97m/s which didnt make sense to me

Answer 7

v is final velocity, u is initial velocity

Answer 8

Better use
\[s=ut+\frac{1}{2}at^2\]

Answer 9

so youre using kinematic equations under the assumption that acceleration is constant

Answer 10

might as well write them all out :)

Answer 11

Help me

Answer 12

youre doing good

Answer 13

there are 4 kinematic equations under constant acceleration

Answer 14

Gotto go i told everything would need to do this problem

Answer 15

i used x=xknot+vknot(t)+.5a(t)^2 where x= position, v=velocity a=acceleration and t= time

Answer 16

i solved for and the plugged it into v=vknot+a(t) and solved for vknot