a car is traveling in a straight line and decelerating at a constant rate. after 3.2 seconds it has traveled 88m and slowed to a speed of 27 m/s what is the initial speed i got 52 m/s

Question

anonymous · Answer

$$v^2-2as=u^2$$

perl · Answer

what does s and u stand for?

anonymous · Answer

Put 
$$a=\frac{v-u}{t}$$

anonymous · Answer

s distance
u initial velocity

anonymous · Answer

and the plug a back into the equation that is what i did but im not sure if my math is right

anonymous · Answer

other people had like 97m/s which didnt make sense to me

perl · Answer

v is final velocity, u is initial velocity

anonymous · Answer

Better use
$$s=ut+\frac{1}{2}at^2$$

perl · Answer

so youre using kinematic equations under the assumption that acceleration is constant

perl · Answer

might as well write them all out :)

anonymous · Answer

Help me

perl · Answer

youre doing good

perl · Answer

there are 4 kinematic equations under  constant acceleration

anonymous · Answer

Gotto go i told everything would need to do this problem

anonymous · Answer

i used x=xknot+vknot(t)+.5a(t)^2 where x= position, v=velocity a=acceleration and t= time

anonymous · Answer

i solved for and the plugged it into v=vknot+a(t) and solved for vknot

anonymous · Answer

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