Question

let z and w be complex numbers such that z+w=0 and z square+w square=1,then mod of z-w=?.

Answer 1

so you want the modular distance of z-w

Answer 2

| z-w| = sqrt ( z-w)^2 =

Answer 3

, sorry messed up

Answer 4

| z- w | = (z-w) conjugat ( z- w)

Answer 5

you need some formulas
http://en.wikipedia.org/wiki/Complex_conjugation

Answer 6

|z|^2 = z* z' , where z' is the conjugate

Answer 7

and |z| is mod z

Answer 8

thanks fr ur help
but i was not getting the answer
i got it now :)

Answer 9

can you type out the answer :)

Answer 10

z^2 + w^2 = 1
(z + wi) (z-wi)= 1

Answer 11

2

Answer 12

do u want a solution?

Answer 13

yes

Answer 14

mark the two equations as (1) and (2)
from (1),we get w=-z,
then 2z square=1
z=+_1/root2
for z=+1/root2,w=-1/root2
for z=-1/root2,w=+1/root2
so,mod of z-w=root2

Answer 15

sorry,i forgot to write root in the previous answr
hope you ll get this solution
its written in a bit puzzling manner :P

Answer 16

makes sense, mod of z-w just becomes the real number root 2

Answer 17

hmmm..right !