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Find the integral of cos^2x dx.please help
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[-sin^2(x)]/2
it's a combination of the power rule thingy and the sinx = cosxdx thingy
and the other thingy
\[\int\limits \cos^{2}x = \frac{1}{2}(1+\cos2x)dx = \frac{1}{2} (x+\frac{1}{2}\sin2x) +c\]
there are a lot of thingies here, aren't there? :))
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Mimi,i understand your steps but not the next one,my final answer is 1\4sin(2x)+1/2x+c which is wrong,it si supposed to be 1\4sin(2x)+2x+c.how do they get 2x?
wolframalpha said something like 1.2(x +sinxcosx) + C haha so embarassing to admit i'm wrong..but i am :))
that's 1/2
mimi is right, so it seems your book is wrong
you can say that again T,@ all-thax for ur help.Igbasallote dont be embarrased one who makes no mistakes never do anything
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