define f(1) in a way that extends f(s)=(s^3-1)/(s^2-1) to be continuous at s=1..please can someone solve this step by step

Question

asnaseer · Answer

factorise the numerator and denominator. you should then be able to cancel a common factor.

anonymous · Answer

the answer is f(1)=3/2 i dont see how they got this...

asnaseer · Answer

well - if you follow my first suggestion then it should all become clear to you.

anonymous · Answer

s^2(s-1)(s+1)/(s+1)(s-1)?

anonymous · Answer

**s^2(s+1)

asnaseer · Answer

your factorisation of the numerator is incorrect

anonymous · Answer

(s-1)(s+1)(s-1)?

asnaseer · Answer

still not correct. do you know how to factorise $s^3-1$?

anonymous · Answer

(s-1)(s^2+s+1)? sorry i took trig last summer so im trying to remember

asnaseer · Answer

that is correct. now you should be able to see which factors cancel out.

anonymous · Answer

one sec...

anonymous · Answer

got it!!!!! thank u , i just gotta remember how to factor down lol

asnaseer · Answer

yw