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Mathematics 16 Online
OpenStudy (anonymous):

define f(1) in a way that extends f(s)=(s^3-1)/(s^2-1) to be continuous at s=1..please can someone solve this step by step

OpenStudy (asnaseer):

factorise the numerator and denominator. you should then be able to cancel a common factor.

OpenStudy (anonymous):

the answer is f(1)=3/2 i dont see how they got this...

OpenStudy (asnaseer):

well - if you follow my first suggestion then it should all become clear to you.

OpenStudy (anonymous):

s^2(s-1)(s+1)/(s+1)(s-1)?

OpenStudy (anonymous):

**s^2(s+1)

OpenStudy (asnaseer):

your factorisation of the numerator is incorrect

OpenStudy (anonymous):

(s-1)(s+1)(s-1)?

OpenStudy (asnaseer):

still not correct. do you know how to factorise \(s^3-1\)?

OpenStudy (anonymous):

(s-1)(s^2+s+1)? sorry i took trig last summer so im trying to remember

OpenStudy (asnaseer):

that is correct. now you should be able to see which factors cancel out.

OpenStudy (anonymous):

one sec...

OpenStudy (anonymous):

got it!!!!! thank u , i just gotta remember how to factor down lol

OpenStudy (asnaseer):

yw

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