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define f(1) in a way that extends f(s)=(s^3-1)/(s^2-1) to be continuous at s=1..please can someone solve this step by step
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factorise the numerator and denominator. you should then be able to cancel a common factor.
the answer is f(1)=3/2 i dont see how they got this...
well - if you follow my first suggestion then it should all become clear to you.
s^2(s-1)(s+1)/(s+1)(s-1)?
**s^2(s+1)
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your factorisation of the numerator is incorrect
(s-1)(s+1)(s-1)?
still not correct. do you know how to factorise \(s^3-1\)?
(s-1)(s^2+s+1)? sorry i took trig last summer so im trying to remember
that is correct. now you should be able to see which factors cancel out.
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one sec...
got it!!!!! thank u , i just gotta remember how to factor down lol
yw
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