How would you find the x intercepts of f(x)=(x+4)^2-3?

Question

anonymous · Answer

Take f(x)=0
So, 0=(x+4)^2 -3
Take 3 to other side,
3=(x+4)^2
Take square root on both sides,
$$\sqrt{3}=x+4$$
$$\sqrt{3}-4=x$$

anonymous · Answer

For finding x-intercepts take F(x)=0
For finding y-intercepts take F(x)=(x+4)^2 -3 with x from (x+4) as 0 :)

anonymous · Answer

Why is the Precalc book telling me to take out -1 of the xs? that's what's been throwing me off..

amistre64 · Answer

duplicate questions are a hassle .....

anonymous · Answer

@Jamroz: You will get correct answer this way as well whatever method suits you, use it.

amistre64 · Answer

dont forget to take "both" sqrts

anonymous · Answer

what do you mean @amistre64?

amistre64 · Answer

what squared makes 3?

there are 2 answers

amistre64 · Answer

x^2 = 3  has 2 results

anonymous · Answer

Yeah so there's 
$$\pm \sqrt{3} -4$$

anonymous · Answer

yeah...

amistre64 · Answer

maybe a more intuitive answer is:

x^2 = 4

(2)^2 = 4

(-2)^2 = 4

so x= 2 and -2

anonymous · Answer

and the vertex is (-4,-3)?

amistre64 · Answer

yes, thats the vertex

anonymous · Answer

wasn't in class today, but given the homework. sorry for sounding stupid, thanks

amistre64 · Answer

yw

anonymous · Answer

at least, not you stay with doubts