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Mathematics 16 Online
OpenStudy (anonymous):

Demonstrate that the digits of a perfect square cannot add to 2, 3, 5, 6, or 8

OpenStudy (anonymous):

Since english is not my first language, what do you mean withe digits of a perfect square?

OpenStudy (anonymous):

The length of the sides?

OpenStudy (anonymous):

like 64: 6+4=10 144: 1+4+4=9

OpenStudy (anonymous):

ahh, nice problem, lemme think about that for a mo

OpenStudy (anonymous):

Hmm, brute force is no option? Simply consider all numbers whose digits add to the respective numbers?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

yes as in, yes it's an option or yes, it's no option?

OpenStudy (anonymous):

consider all possible numbers

OpenStudy (anonymous):

2 = 2 or 11 3 = 3 or 21 or 12 or 111 5 = 11111 or 11112 or 11121 or 11211 or 12111 or 21111 or etc etc etc

OpenStudy (anonymous):

Simply show that all those numbers are not perfect squares It's a bit of work, but it'd work

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