is this limit correct? been thinking about it..

Question

anonymous · Answer

$$\lim_{x \rightarrow \infty} x/sinx$$

anonymous · Answer

and i think it equals infinity using the squeeze/sandwich theorem, as 

-x <= x/sinx <= x 
both -x and x continue to infinity
therefore x/sinx does.

i can only find information on sin(x)/x (stupid famous limit) so this one has been tricky lool

anonymous · Answer

x goes to ininfity, sine fluctuates between -1 and 1

anonymous · Answer

so there is no limit. is undefined where sine is zero, and goes to plus infinity and minus infinity at vertical asymptotes

ash2326 · Answer

using sandwich theorem both upper and lower bounds should converge at the same point
here x= $\infty$
-x--->$-\infty$
so limit doesn't exist

anonymous · Answer

no sandwiches here, that is for sure. maybe a picnic though

anonymous · Answer

alright, gracias gracias, I was actually thinking there was no limit for this problem but my professor said there was earlier today. Either I wrote the problem down wrong, or in the midst of his thinking process he was thinking of a diff. limit lol. I have been confused for awhile!