factor completely 3x^4 + 6x^3 -45x^2

Question

anonymous · Answer

3x^2(x^2+2x-15)
3x^2(x+5)(x-3)

anonymous · Answer

(3x)(x)(x+5)(x-3) techincally fun

anonymous · Answer

3(x)(x)(x+5)(x-3) if we want to TRULYYY seperate everything here

anonymous · Answer

well it said completely

anonymous · Answer

hahahaha

anonymous · Answer

$$3x ^{2}(x-3)(x+5)$$

anonymous · Answer

plz explain how it became (x-3)(x+5)

anonymous · Answer

3x^4 + 6x^3 -45x^2 <------- we started with that

notice that all these terms have a common factor, which is 3 and x*x or x^2.. so if we factor that out it becomes...

3x^2(x^2+2x-15) 

here we need to find two numbers that multiply to 15, but add to 2. 5 and 3 will do the trick. This is a method of factoring. along the lines of (x+a)(x-b).

3x^2(x+5)(x-3) 

notice if you multiply (x+3)(x-3) out, you will get x^2-3x+5x-15, which is x^2 +2x -15, and if you multiply that by 3x^2 you get the original expression.

anonymous · Answer

got it thnxx