what is the third order derivative of (x^-(1/2x))/(x^x) in algebraic terms?
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OpenStudy (anonymous):
\[x ^{-1\div2x}\div x^{x}\]
OpenStudy (anonymous):
Huh?
OpenStudy (anonymous):
Huh?
OpenStudy (anonymous):
ellipsis
OpenStudy (anonymous):
ellipsis
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OpenStudy (king):
hashir????
OpenStudy (anonymous):
hashir????
OpenStudy (anonymous):
the first one \[y'=-1.5*x ^{-1.5x}*(lnx+1)\]
OpenStudy (anonymous):
bro i am jst enjoying !!
OpenStudy (anonymous):
in non-logistical terms?
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OpenStudy (anonymous):
in non-logistical terms?
OpenStudy (lalaly):
first derivative\[\large{\frac{x^{-\frac{1}{2}x}}{x^x}= x^{-\frac{3}{2}x}}\]let \[y=x^{-\frac{3}{2}x}\]\[lny=\ln(x^{-\frac{3}{2}x})\]\[lny=-\frac{3}{2}xlnx\]now take derivative of both sides\[\frac{1}{y}y'=-\frac{3}{2}lnx-\frac{3}{2}\]\[y'=(\frac{-3}{2}lnx-\frac{3}{2})y\]
OpenStudy (anonymous):
first derivative
x−12xxx=x−32x
let
y=x−32x
lny=ln(x−32x)
lny=−32xlnx
now take derivative of both sides
1yy′=−32lnx−32
y′=(−32lnx−32)y
OpenStudy (lalaly):
Hashir stop this please
OpenStudy (lalaly):
He left:D
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OpenStudy (anonymous):
thee second
\[y''=1.5x ^{-1.5x}*(1/x+1.5(lnx+1)^2)\]