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Mathematics 14 Online
OpenStudy (anonymous):

What are the solution intervals for |2x – 1| + 6 > 9?

hero (hero):

|2x – 1| + 6 > 9 |2x – 1| > 3 -3>2x – 1 > 3 -2>2x>4 -1>x>2 x<-1 x>2

OpenStudy (anonymous):

argh

hero (hero):

lol, I knew you would say something

OpenStudy (anonymous):

@hero, answer is correct, method is all wrong

hero (hero):

lol, but it gets the right answer. I could care less

OpenStudy (anonymous):

in particular, could you explain what this means? -1>x>2

OpenStudy (anonymous):

in fact the only reason it gets the right answer is because you make a leap at the end in your mind

hero (hero):

It's just an intermediary step in solving the problem. It means nothing until the solution is written

OpenStudy (anonymous):

you write -1>x>2 x<-1 x>2 but the first statement is entirely false

hero (hero):

Just another one of my weird methods

OpenStudy (anonymous):

lets do it correctly first of all as you can see the answer is two intevals, so you have to write two intevals, not one

hero (hero):

-1>x>2 is false, therefore, split into piecewise

hero (hero):

x<-1 x>2

OpenStudy (anonymous):

\[|2x – 1| > 3\] \[2x-1<-3\text { or } 2x-1>3\] \[x<-1\text { or } x>2\]

OpenStudy (anonymous):

there is no such thing as \[-1>x>3\] because this implies \[-1>3\]

OpenStudy (anonymous):

both of you are correct

OpenStudy (anonymous):

like writing \[-3=2x+1=3\]

hero (hero):

-1>x>2 according to my logic means the same as the or statement you've written above.

OpenStudy (anonymous):

"and" is not the same as "or"

hero (hero):

The statement I've written above doesn't mean and, it means or

OpenStudy (anonymous):

actually it means and

hero (hero):

not in this case

OpenStudy (anonymous):

and that is clear because you would not claim that \[-1<x<3\] means "or" because that would be the whole real line

hero (hero):

a>x>b means or a<x<b means and

OpenStudy (anonymous):

???

hero (hero):

lol

OpenStudy (anonymous):

\[3>x>2\] means "or" and \[2<x<3\] means "and" ?????

hero (hero):

That's not what I wrote satellite

OpenStudy (anonymous):

you wrote a>x>b means or a<x<b means and

hero (hero):

Yes

OpenStudy (anonymous):

presumably a and b are variables

OpenStudy (anonymous):

\[6>x>0\] means or then

hero (hero):

You can't stick 2 and 3 wherever you want. You have to follow protocal

OpenStudy (anonymous):

so if i solve an inequality and get \[3>x>1\] that means, since this is an "or" statement, the whole real line is a solution. interesting

hero (hero):

You're not following my logic correctly that's why.

OpenStudy (anonymous):

no i am pointing out why your logic is incorrect

hero (hero):

Nope, you intentionally switched 2 and 3, intentionally creating a false fallacy

OpenStudy (anonymous):

\( |2x – 1| > 3 \implies 2x-1 > 3 \) or \( 2x-1 <-3 \) but not both.

OpenStudy (anonymous):

i know exacty what you mean. in your head you are thinking that if you write \[5<x<2\] (which is impossible) that since \[5>2\] you really mean \[x<2\text { or } x>5\] but that is not what it says

hero (hero):

I always get the right answer, so I don't worry about that one misstep

hero (hero):

and also, if this ever happens: 3>x>-1 I just simply reverse it to this: -1<x<3

OpenStudy (anonymous):

well at least we recognize that it is a misstep...

hero (hero):

Actually, I retract that statement. It is not a misstep, but rather, an intermediary step.

OpenStudy (anonymous):

yes, a wrong one!

razor99 (razor99):

hero cld u help this girl.

OpenStudy (anonymous):

\[|x|<p\iff -p<x<p \text{ for } p>0\] \[|x|<p\iff x<-p \text { or } x>p\] "or" aint "and"

OpenStudy (anonymous):

AY I NEED YOU GUYS HELP GO TO THE QUESTION I JUST POSTED

OpenStudy (anonymous):

\[|x|>p\iff x<-p \text { or } x>p\]

razor99 (razor99):

plzzzzzzzzzzzzzzzzzzzzz help heerrrrooooooooooooo

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