What are the solution intervals for |2x – 1| + 6 > 9?
|2x – 1| + 6 > 9 |2x – 1| > 3 -3>2x – 1 > 3 -2>2x>4 -1>x>2 x<-1 x>2
argh
lol, I knew you would say something
@hero, answer is correct, method is all wrong
lol, but it gets the right answer. I could care less
in particular, could you explain what this means? -1>x>2
in fact the only reason it gets the right answer is because you make a leap at the end in your mind
It's just an intermediary step in solving the problem. It means nothing until the solution is written
you write -1>x>2 x<-1 x>2 but the first statement is entirely false
Just another one of my weird methods
lets do it correctly first of all as you can see the answer is two intevals, so you have to write two intevals, not one
-1>x>2 is false, therefore, split into piecewise
x<-1 x>2
\[|2x – 1| > 3\] \[2x-1<-3\text { or } 2x-1>3\] \[x<-1\text { or } x>2\]
there is no such thing as \[-1>x>3\] because this implies \[-1>3\]
both of you are correct
like writing \[-3=2x+1=3\]
-1>x>2 according to my logic means the same as the or statement you've written above.
"and" is not the same as "or"
The statement I've written above doesn't mean and, it means or
actually it means and
not in this case
and that is clear because you would not claim that \[-1<x<3\] means "or" because that would be the whole real line
a>x>b means or a<x<b means and
???
lol
\[3>x>2\] means "or" and \[2<x<3\] means "and" ?????
That's not what I wrote satellite
you wrote a>x>b means or a<x<b means and
Yes
presumably a and b are variables
\[6>x>0\] means or then
You can't stick 2 and 3 wherever you want. You have to follow protocal
so if i solve an inequality and get \[3>x>1\] that means, since this is an "or" statement, the whole real line is a solution. interesting
You're not following my logic correctly that's why.
no i am pointing out why your logic is incorrect
Nope, you intentionally switched 2 and 3, intentionally creating a false fallacy
\( |2x – 1| > 3 \implies 2x-1 > 3 \) or \( 2x-1 <-3 \) but not both.
i know exacty what you mean. in your head you are thinking that if you write \[5<x<2\] (which is impossible) that since \[5>2\] you really mean \[x<2\text { or } x>5\] but that is not what it says
I always get the right answer, so I don't worry about that one misstep
and also, if this ever happens: 3>x>-1 I just simply reverse it to this: -1<x<3
well at least we recognize that it is a misstep...
Actually, I retract that statement. It is not a misstep, but rather, an intermediary step.
yes, a wrong one!
hero cld u help this girl.
\[|x|<p\iff -p<x<p \text{ for } p>0\] \[|x|<p\iff x<-p \text { or } x>p\] "or" aint "and"
AY I NEED YOU GUYS HELP GO TO THE QUESTION I JUST POSTED
\[|x|>p\iff x<-p \text { or } x>p\]
plzzzzzzzzzzzzzzzzzzzzz help heerrrrooooooooooooo
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