Question

The positive difference between two consecutive even perfect squares is 268 . Compute the larger of the two squares.

Answer 1

so it is (x+1)^2-x^2=268

Answer 2

says even right, so maybe
\[(2n+2)^2-(2n)^2\]

Answer 3

x^2+1^2-x^2=268
x^2+1-x^2=268
x^2-x^2=268-1
0=267
I did something wrong....

Answer 4

oh, I see

Answer 5

2n^2+4-2n^2=268
2n^2-2n^2=264

Answer 6

0=264?!?!

Answer 7

i made a mistake

Answer 8

\[(2n+2)^2-(2n)^2=8n+4\]

Answer 9

i forgot to square the 2!!

Answer 10

where didya get the "8n"?

Answer 11

\[8n+4=268\]
\[n=33\]
\[2\times 33+2\] is your answer

Answer 12

algebra

Answer 13

\[(2n+2)(2n+2) -4n^2\] etc