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Physics 8 Online
OpenStudy (anonymous):

im confused as to how velocity times mass combined is equal to force net times time

OpenStudy (asnaseer):

\[\begin{align} F&=ma\\ a&=\frac{dv}{dt}\\ F&=m\frac{dv}{dt}\\ \therefore F\cdot dt&=m\cdot dv \end{align}\]

OpenStudy (anonymous):

v X m=F x t , which is referred to as impulse rewrite the equations vX m= m x a x t F= m X a v X m= m X (v/ t) x t ; a- v/t vm= vm

OpenStudy (anonymous):

i mean in terms of momentum

OpenStudy (mani_jha):

Whenever a force is applied, there HAS to be a change in momentum. Just think about it, the larger the force, the larger its change in momentum(mostly velocity changes, mass is constant). So the momentum change increases with force. Now, when u try to stop a running car with ur hands, it would take a long time. But when two cars collide, the car stops instantaneously. As you see, the other car has applied a much greater force than you, and has stopped the car in extremely less time. So, the greater the force, the less the time required to change the momentum \[F=dp/dt\] or \[Fdt=dp\] \[Fdt=mdv\] You should have asked mass times change in velocity, not mass times velocity

OpenStudy (anonymous):

yes, momentum is what it is. Sorry the change in momentum is impulse. The fact that they are equal "is" tells you that it works.

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