Question

2^2x-1 < 3^3x-2

Answer 1

Please add grouping symbols so that 2^2x-1 < 3^3x-2 can be correctly read.

For example, is i t[ 2 ^ (2x)] - 1< 3^(3x) - 2 ? Click on the blue Draw button and write it there if you like. Thanks.

Answer 2

2^(2x-1) < 3^(3x-2)

Answer 3

3rd question of the attachment
...I also need to solve the first question..if you can kindly solve it for me?

Thanks

Answer 4

2 ^ (2x-1) = 3 ^ (3x-2)

log [2 ^ (2x-1) =log [ 3 ^ (3x-2)]

(2x-1) log 2 = (3x-2) log 3 and ....

Answer 5

(2x-1) log 2 = (3x-2) log 3
.301 ( 2x-1) = .478 (3x-2)
x = .787 approx

Answer 6

so we have to solve by using log value..is there any other way?..and thanks :)

Answer 7

I don't think so but what is the name of the unit from which this problem came.

Answer 8

hummmm...can you please try first problem (check the attachment)... :)

Answer 9

I need to see the solution...this is just a sample question for an entrance exam..so it is necessary to have the solution for my practice.. Okai I will wait..and thank you so much :)

Answer 10

take ln on both sides for C

Answer 11

Something is not going correctly with this absolute value problem. I'll need a little more time.

The suggestion made above about using "ln" is a suggestion to use natural logs (base e logs) and doesn't answer your question about doing the problem without logarithms.

Answer 12

I posted the two problems to see if any other ideas pop up. Meanwhile, I'm back on the absolute value problem. :)

Answer 13

Watch the "progress" here:

http://openstudy.com/study#/updates/4f372b2ce4b0fc0c1a0d3ae8

Answer 14

it 4:00am here..and im going to sleep now..i'll check later ..and thanks for your efforts :)

Answer 15

Okay. We will continue working, and I will post the solution or a link to the solution here for you to see. It's just after 10 pm for me so I have some working time left.