Question

calculate mass of caco3 required to liberate 10 litres of co2 at stp

Answer 1

CaCO3=CaO+CO2.
10 litres of co2= 10/22.4 moles at STP.
So no of moles of CaCO3=10/22.4.
So,
\[mass/molecular weight = 10/22.4\]
Molecular weight = 100
Calculate mass

Answer 2

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