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OpenStudy (aravindg):
calculate mass of caco3 required to liberate 10 litres of co2 at stp
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OpenStudy (mani_jha):
CaCO3=CaO+CO2. 10 litres of co2= 10/22.4 moles at STP. So no of moles of CaCO3=10/22.4. So, \[mass/molecular weight = 10/22.4\] Molecular weight = 100 Calculate mass
OpenStudy (aravindg):
wow thx i hav another qn too pls help
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