Question

can anyone integrate this (1+x^(-2/3))^1/2 I just can't get it my substitution won't work

Answer 1

this is difficult

Answer 2

\[\int u^{1/2}du=\frac 23 u^{3/2}\]
in essense

Answer 3

Nope,,, it is easy, use the substitution.. t=x^(-1/3)...

Answer 4

\[\frac{d}{dx}(1+x^{-2/3})=\frac{-2}{3}x^{-5/2}\]bummer

Answer 5

alomst thought that out right lol

Answer 6

(1 + x^{2/3})^{3/2}

Answer 7

http://www.wolframalpha.com/input/?i=integrate++%281%2Bx%5E%28-2%2F3%29%29%5E1%2F2

wolf gives some steps but it looks like a pain to me

Answer 8

lucifur how did you get that? that's the right answer but what substitution did you do to get it?

Answer 9

take t = x^2/3

Answer 10

take t = x^2/3
dx = (3/2) t^-1/2 * dt