Question

help me
lim as x-->1
\[\left(\begin{matrix}\sqrt[4]{2x-1}+\sqrt[5]{x-2} \\ x-1\end{matrix}\right)\]

Answer 1

Is is combinatorics?

Answer 2

same as asking for the derivative of the numerator at x =1

Answer 3

i am assuming that was a fraction

Answer 4

what is problem? it makes no sense to me :(

Answer 5

oh lol

Answer 6

he/she says lim as x-->1

Answer 7

that is my assumption, except i meant x goes to 1, not zero

Answer 8

\[\lim_{x\rightarrow 1}\frac{\sqrt[4]{2x-1}+\sqrt[5]{x-2}}{x-1}\]

Answer 9

this is asking for
\[f'(1)\] where
\[f(x)=\sqrt[4]{2x-1}+\sqrt[5]{x-2}\]

Answer 10

Wow, sat that was fast!

Answer 11

@lazypig you got this?