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the integral of sec 2x * tan 2x dx?
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whats the derivative of sec?
\[\int\limits_{}^{} \sec (2x) \tan (2x)dx\]\[u = 2x, \frac {1}{2}du = dx\]\[\frac {1}{2} \int\limits_{}^{} \sec u \tan u du = \frac {1}{2} \sec u = \frac {1}{2} \sec 2x\]
+C
the 2x pops out a 2 that needs to disappear so id say 1/2 sec(2x) yep
+C lol
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Always the constant... Damn.
yes i contributed something lol
Rogue, good job!
lets try to avoid the "d" in the future please :)
I'll try ;)
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i like plus K
so the antideriative of sec * tanx is secx?
Yup =]
+ C
yes, anyway, it's not in my cal book, thank you
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