Question

physics 2

see the photo please and help Me :(

Answer 1

this is the Q

Answer 2

i think these formulas for that :
F=qe &F=ma & this equation :\[y=(1/2)at ^{2}\]
if simplify these we have:
\[y=(1/2)(qE/m)t ^{2}\] solve this with t=1
E is electric field act on drop

Answer 3

sorry in first formula F=qE not f=qe

Answer 4

why t=1

Answer 5

first say me by the times means any 1 second?

Answer 6

if no put t=L/V in the
y=(1/2)at^2

Answer 7

for m use this\[\rho=m/(4/3\Pi r ^{3})\]

Answer 8

did you get it?

Answer 9

wait a minite

Answer 10

sure

Answer 11

not correct

Answer 12

y?

Answer 13

can you explain

Answer 14

i used mastering physics and it tell me its wrong

Answer 15

i have another Q can u help me

Answer 16

i don't solve please wait what's your Q?

Answer 17

this it

Answer 18

m=3.35*10^-10 right?

Answer 19

wtich one

Answer 20

please see the second Q

Answer 21

ohh this is a another ask am iright?

Answer 22

please help me

Answer 23

second attachment is another ask ?

Answer 24

yes it is another Q

Answer 25

i think
x=vt

Answer 26

these asks solve with above formulas

Answer 27

wrong answer

Answer 28

asks end is magnitude of deflection or path that charge move ? if deflection is right use \[y=0.5(qE/m)t ^{2}\]