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How do you simplify (-1+sqrt3) over (2-sqrt 3)?
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divide by the conjugate of the denominator
\[\frac{-1+\sqrt{3}}{2-\sqrt{3}}*\frac{2+\sqrt{3}}{2+\sqrt{3}}\]
\[(2+\sqrt{3})\] top and bottom
Okay I think I wrote it wrong, it's actually 2 times sqrt 3 on the bottom, not 2 - sqrt 3. Sorry!
Thank you so much for the replies!
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\[\frac{-1+\sqrt{3}}{2\sqrt{3}}*\frac{\sqrt{3}}{\sqrt{3}}\]
You want a number that'll rationalize the denominator, \[(\sqrt{3})^2=3\]
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