Question

ok im back with a similar problem...

Answer 1

Which is where???

Answer 2

if f(x)=8x^3 then

f(x+h)-f(x)/h = Ax^2+Bxh+Ch^2

Find constants A, B, and C.

Answer 3

i know the steps to this thanks to asnaseer, but what do i do when i get 8(x+h)^3 - 8x^3

Answer 4

how do i put it in the (a+b)(a-b) form?

Answer 5

would it be (8x+h +8x)(8x+h-8x) ???

Answer 6

its a cubic so i dont think we get to make it into a quadratic

Answer 7

what do we do here then?

Answer 8

im gonna go take a shower. be back in a bit.

Answer 9

1 3 3 1
x^3 x^2 x
h h^2 h^3
-------------------\[x^3+3x^2h+3xh^2+h^3\]
is our results; *8

Answer 10

sooo

\[\frac{\cancel{8x^3}+24x^2h+24xh^2+8h^3 \cancel{- 8x^3}}{h}\]
\[\frac{\cancel{h}(24x^2+24xh+8h^2) }{\cancel{h}}\]
\[24x^2+24xh+8h^2=other.stuff\]

Answer 11

and from that you should be able to compare coeefs

Answer 12

how did you start it all off? could you explain in words