Question

How do you find the domain of f(x)=lnlnlnx

Answer 1

I know you know it sat...

Answer 2

x>e^e
right?

Answer 3

domain of
\[ln(x)\] is \[x>0\]
so domain of
\[\ln(\ln(x))\] is \[\ln(x)>0\]
\[x>1\] lather rinse repeat

Answer 4

i think you might be off by one @turing

Answer 5

d'oh!

Answer 6

For ln(x), x>0. We can agree on this, right? For no n can e^n=<0. However, ln(x) can come out to be ln(x)<0, unless x>e (otherwise for e^n n<0). So the domain of ln(ln(x)) must have x>e.

Answer 7

did i mess up? let me check

Answer 8

no i don't think so

Answer 9

no you guys both agree
I was wrong

Answer 10

\[\ln(\ln(\ln(x)))\] must have
\[\ln(\ln(x))>0\] must have
\[\ln(x)>1\] must have
\[x>e\]

Answer 11

Woo!

Answer 12

Thanks guys!!!

Answer 13

Omg i actually understand it! Thank you, saved me a good hour of wasting time going to my school's tutoring center.