what is the net ionic equation of this (including phases)

Cu(ClO4)2 (aq) + Na2S ==CuS(s)+2NaClO4(aq)

Question

what is the net ionic equation of this (including phases)

Cu(ClO4)2 (aq) + Na2S ==>CuS(s)+2NaClO4(aq)

xishem · Answer

The net ionic equation is the entire equation minus all spectator ions.

Spectator ions are all species which occur in aqueous solution on both the reactants and products sides of the equation. So first try splitting each compound up into its respective ions first.

xishem · Answer

So...$$Cu^{2+}(aq)+2ClO_4^-(aq)+2Na^+(aq) +\S^{2-}(aq)  \rightarrow$$$$Cu^{2+}(s)+\S^{2-}(s)+2Na^+(aq)+2ClO_4^-(aq)$$I don't know why the "S"'s are showing up weird, but alright.

The sodium and perchlorate ions are the ions which show up in aqueous solution on both sides of the equation, and so they are the spectator ions. Removing them, we get the net ionic equation...$$Cu^{2+}(aq)+\S^{2-}(aq) \rightarrow CuS(s) $$