Question

please help!!!!

Answer 1

Have you fallen and are unable to get up?

Answer 2

I guess I have fallen into a "math trap" then....

Answer 3

It was an obscure reference joke. Go on.

http://www.youtube.com/watch?v=bQlpDiXPZHQ

Answer 4

A train left Seattle for Portland. In Tacoma half the passengers got off. In Olympia 10more passengers got off. In Centralia half the remaining passengers got off. In Chehalis 5 more passengers got off. In Vancouver three-fouths of the remaining passengers got off. The train reached Porland with only 5 passengers. The only passengers who left the train are those described above and no one boarded the train after it left Seatle. How many passengers were on board initially?

Answer 5

Oh God, words. Alright, I'll read it. Hold on.

Answer 6

I know, thanks.

Answer 7

We start with n passengers. At Tacoma, it becomes n/2. In Olympia, it becomes (n/2)-10. In Centralia, it becomes ((n/2)-10)/2. In Chehalis, it becomes ((n/2)-10)/2-5. In Vancouver, it becomes (1/4)(((n/2)-10)/2-5). We know that at the end it has 5 passengers, and no one else boarded. Thus, (1/4)(((n/2)-10)/2-5)=5, or ((n/2)-10)/2-5=20, or ((n/2)-10)/2=25, or (n/2)-10=50, or n/2=60, or n=120.

My basic math might be wrong (I doubt it), but the steps are correct. You should go through them starting with the equation (1/4)(((n/2)-10)/2-5)=5 that we know to be true.

Answer 8

I believe that is correct. Thank you very much!!!