JUST #28. http://screensnapr.com/v/wmqb1W.png
\[\vec u\cdot\vec v=|u||v|\cos\theta\]
Why did you specify the absolute value for a dot product, Turing?
Thats not absolute value, its magnitude.
normally it has two lines around it, but that looks messy on here
He could have put || but yeah :P
Oh, alright.
so just 100*250(pi/6)
no cosine!
no wait thats like 740000 degreees
HHAHAHA I WAS LIKE OMG THIS IS CRAZY
gotta have that cosine or it's not worth the paper it's printed on...
I'm still pretty sure this answer is wrong.. 24998..
let me see what I get...
I got 21650...
21651 rounded
which is reasonable, they are big vectors
u=100, v=250, theta=(pi/6) 100*250=25000*cos(pi/6)=24998.
Calculator is 100% sure in degree too.
perhaps you are in degree mode?
Oh......
lol that's not a good thing
if it's got pi in it you're almost certainly in radians
I was just doing angle between vectors which said make sure it's in degree mode :P
cos(pi/6) is a known special trig value: \[\cos\frac\pi6=\frac{\sqrt3}2\]and I'm gonna guess the other excercise you did did not have pi degrees in it
Oh! a quick question, how do you find if two vectors are orthogonal or parallel? <15,45>
and <-5,12> sorry :P
again, same formula if they are parallel what is the angle between them?
And no, it was a different section :)
Isnt it just 15*-5+45*12? 465.
\[\vec u\cdot\vec v=|u||v|\cos\theta\]if u and v are parallel, what is theta? what about if they are perpendicular?
right, and how did we know those vectors in your example were orthogonal?
equals 0 then vectors are orthogonal
But does 465 mean anything?And how do you know if they are parallel?
besides graphing them of course
can you see why from this formula?\[\vec u\cdot\vec v=|u||v|\cos\theta\]that will answer your question, just answer mine what is the angle between two orthogonal vectors?
Well they're perpindicular :P
perpendicular.
and a perpendicular angle is how many degrees?
180 or 90.
just 90... and what is the cosine of 90 degrees?
zero
OH! I get it :D
Not the parallel part but I get the reasoning of the 0.
so when our formula becomes\[\vec u\cdot\vec v=|u||v|\cos\frac\pi2=0\]that's why that works yeah! so what about parallel? what is the angle there?
pi/2=90 degrees btw...
|dw:1329975086069:dw|what is theta between these two parallel vectors?
What..
theta is the angle what is the angle between them?
Yes, I know, but I have no idea!
you can always draw vectors on top of each other to compare the angle|dw:1329975259129:dw|it looks like the angle is 0 degrees (or 180 degrees) what is the cosine of zero degrees?
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