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Mathematics 20 Online
OpenStudy (anonymous):

Help!!!!

OpenStudy (anonymous):

A long time ago in England that had a coin called the Guinea, which was worth 21 shillings. They also had a coin called the Crown, which was worth 5 shillings. What is the largest number of shillings which you could not equal with a combination of Guineas and Crowns?

OpenStudy (anonymous):

Wait this is challenging. gimme a moment

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

Hmm my answer would be 74. I am not sure if it is correct. But here is my reasoning. the things we have to understand that is as the number beomces bigger, it becomes easier to fit a combination of crowns and guinea in. because of the number 21. to get lets say a number of 2341. to satisfy the ones place, meaning the number 1 in 2341. u need to have only 1 guinea worth 21 shillings. the rest can be crowns. So therefore there is a limit to the maximum value, and then for digits 0-9. if u look carefully, 0 and 5 can be satisfied by using crowns. 6-9 can be simplified by using 1 crown to get the values 1-4. therefore the answer definitely have a 4 in the ones places. 21*4 = 84, this is the minimum solvable value with 4 in the ones position. Thus the answer would be the previous number with 4 in the ones place, meaning 74. Hope you get what i mean, and hope im right

OpenStudy (anonymous):

The explanation makes perfect sense to me, but 74 is incorrect.

OpenStudy (anonymous):

damn.. -.- do u have the correct answer, maybe i can work my way backwards?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

Thank you for trying though.

OpenStudy (anonymous):

OMG i know already, the answer is 79. 79 minus 5 would give u 74 which we determine earlier is unsolvable. so this is the true maximum value

OpenStudy (anonymous):

I hope this is finally correct. What a glaring mistake by me haha

OpenStudy (anonymous):

Thank you so much!!!! That is correct!

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