derive an equation who's coefficients are integers and who's roots are \(\frac{1}{2} \) and \(\ 7 \) . I'm getting \(\ 2x^2-15x+7 \) but the book says \(\ 2x^2 +13x-7 \) ... who's right, who's wrong, how do u arrive at the answer?
youre right ant the book is wrong
Saso is always right. :)
i'm tired of this book and seriously want to get rid of it now but it has so many good review questions with wrong answers :@ i find more wrong answers than right answers it's so bad :@
Did you confirm with Wolframalpha or does it not compute these problems?
i think certain questions don't even require the use of a calculator, not to even speak of wolfram
I find it quite hard to believe that the book is inaccurate
well in ghana you can find such books and :@ i hate it!!!! believe it or not my teachers recommend it because of it's questions, not because of it's answers, sucks :@@@@@@
some sections are treated well, others, it's just so bad like i said, i find more wrong answers than right ones... at some sections :@@@@@@@@@@@@@@@
Ah I see.
kat, the book is inaccurate in this case, the books answer implies the roots to be -7 and 1/2
I understand why it is inaccurate but I find it quite hard to believe that books trying to guide students for examinations are inaccurate.
do so many books have similar typos? i find this one odd
Most probably
Okay kat, tell me how I should we approach "this kinds" of problems ;)
It's spelled whose btw
sorry my mistake lol, thanks for the heads up on that one :)
ffm kat might not answer u lol, it's "too early" (or too late kat) for her to solve maths
I haven't been in bed..my brain feels fried.
you dont' need brain to solve this ...
What do you want?
eyes and figures to type ..
2x^2 +13x - 7 7*2 = 14 14 and 1 subtract to 13 (x+14/2) (x-1/2) x = -7, 1/2 ---------------------- otherwise: (x+7)(2x+1) = 2x^2 +15x - 7
x^2 - (sum of the roots)x + product of the roots
roots are 7 and 1/2 => x=1/2 or x=7 =>x-7=0 or2x-1=0 hence (2x-1)(x-7)=0 and 2x^2-15x+7=0 hence expression with 1/2 and 7 as roots is 2x^2-15x+7
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