Question

Hey guys... Here's a proof I am working on. I have to find out the untrue step in this proof. It's the 1+1 = 0 proof. Here are the steps:

1) 1 + 1 = 1 + √1

as we can take the value of √1 for 1

2) = 1 + √-1 * -1

because -1 * -1 is + 1

3) = 1 + √-1 * √ -1

now we can separate the multipliers and finally as we can denote √-1 with complex charecter i

then


4) = 1 + i * i

which can be written with squares like this


5) = 1 + i²

as we know that i = √-1

and (√a)² is a with it we can write it like this now


6) = 1 + (√-1)²

7) = 1 + (-1)

as + * - is -

Answer 1

Here is where I think it is wrong: I don't think you can just separate the multipliers (now we can separate the multipliers and finally as we can denote √-1 with complex character) Is that right?

Answer 2

if you need a better example, you can find the proof online by just typing in in 1+1 = 0 proof

Answer 3

wer'z d rong step??

Answer 4

That's what I need help figuring out!

Answer 5

i don't think you can write (sqrt(-1))^2 = -1

Answer 6

lol......i^2 =-1 ..so c iz right..

Answer 7

i^2=-1(according to complex no.)

Answer 8

i thinkk .ur stps r right ... wat makes u think dat u r goin wrong??

Answer 9

because it's a trick question. There is suppose to be a wrong step in there.

Answer 10

hold on, I figured it out. I'll upload the answer in a sec

Answer 11

\[\int\limits(1/x)dx=\]

Answer 12

1/x=u dv=dx

Answer 13

hence , du=-1/x^2 v=x

Answer 14

hence ... uv -\[\int\limits v.du\] =

Answer 15

int(1/x)=x/x+int(1/x)

Answer 16

hence

0=1

Answer 17

therefore 1+1=0+0=0