A box of mass 16kg is pulled from rest a distance of 5m across a smooth horizontal floor by a cable inclined at to the horizontal. Find the work done by the tension in the cable given that its magnitude is 25N.
Work = (Force) x (Displacement in the direction of force) Here, you have the force and the displacement. Hence you just need to calculate.
Make sense? Talk to me.
could you give me the answer?? make sense :D
Well, the force is 25 N and what's the distance?
5m
but there is an angle given right?? why don't we include in the calc??
Ah, what is that angle?
Are you given a specific value?
60 degree,and why they give us mass??
cos 60 is 0.5
As a distraction. Hence the force in the direction of motion, call it the x-direction, is \[ F_x = F \cos(60) = 25 \frac{1}{2} \] Hence work, W, \[ W = F_x . d = \frac{25}{2} \cdot 5 \ \ \ N \cdot m \]
Yes, sorry about that.
thanks :D
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