Question

0.3(y-2)>0.4(1+y)

Answer 1

go for it ACCESS!

Answer 2

To get rid of the decimals (it is easier to work with solid integers), we can multiply everything by 10.
3(y-2)>4(1+y)
Then, we will distribute the 3 and 4 on each side respectively.
3y-6>4-4y

Think you can get it the rest of the way at this point? :)

Answer 3

Hmm... well, I'll just go the rest of the way so you don't have to wait if you're away... :p

3y-6>4-4y (add 4y to both sides)
7y-6>4 (add 6 to both sides)
7y>-2 (divide by 7, its positive so we don't need to change any signs)
y>-2/7

Answer 4

what happens is you dont want to multiply everything my 10?

Answer 5

oops! my mistake. 4+6 = 10!

so, 7y>10
y>10/7.

It would still work out, but you'd probably have more decimals to work with.

Answer 6

can't you you just distribute the decimals and go from there would that work?

Answer 7

Yep.

Answer 8

alright i just did that and got 0.3y-0.6>0.4+0.4y

Answer 9

Yeah, so, if you work to get y by itself, you'd do...
0.3y-0.6>0.4-0.4y (Add 0.4y to both sides)
0.7y-0.6>0.4 (add 0.6)
0.7y>1 (divide by 0.7, or equivalently 7/10)
y>1/(7/10) (dividing by a fraction means multiplying by its reciprocal, 10/7)
y>1*(10/7)
y > 10/7

Answer 10

It certainly works to do it that way, but I think multiplying by 10 at the beginning makes it a bit easier since you don't have to think about that "divide by 0.7" stuff.

Answer 11

i came up with y>1/0.7?

Answer 12

0.7 is the same as 7/10
If you divide by a fraction, then you instead multiply by its reciprocal (just some rule of algebra)
So, 1/0.7 = 1/(7/10) = 1*10/7 = 10/7

Answer 13

Alright thank you Access you have been a great help thank you for guiding me through it and helping me out, and answering my questions really appreciate it! thank you!

Answer 14

No problem. Glad to help! :)