Question

I need to integrate: (x-1) / (x^2 +1) =
a) substitute, parts, or partial fractions and how do I know to use that method?

b) how to I access the equation tool?

thanks

Answer 1

don't want to use partial fraction because
\[x^2+1\] does not factor over the integers. you would get
\[(x+i)(x-i)\] and then you would have an complex integral

Answer 2

isn't that inverse tangent on the bottom

Answer 3

Rewrite that as:
x/(x^2+1) - 1/(x^2+1)

Answer 4

use u = x^2+1 for the first half, the 2nd one's just tan^-1(x)

Answer 5

what bahrom said. break it in two. one is log by a u-sub, other is inverse tangent

Answer 6

Just split it into two terms x/(x^2+1) + 1/(x^2+1).
substitute for the first term x^2 +1 =t and second term is directly tan inverse.
So the answer ln(x^2+1)/2 + tan inverse x.

Answer 7

See I feel like a genius! Satellite supports my answer!

Answer 8

soooo once again I am making this stuff harder than I need to