Question

how do you find the zero(s) of the function f(x)=x^2-x+(5/4)

Answer 1

4x^2 - 4x + 5 = 0

Answer 2

why would you do that? common denominator?

Answer 3

no because it looks a little prettier.. just multiply out by 4

Answer 4

now use the discriminant formula

Answer 5

discriminant formula..? feeling braindead tonight, ahhh

Answer 6

-b/2a? no..

Answer 7

that's slope/axisofsymmetry

Answer 8

D = b^2-4ac
x1 = (-b-sqrt(D))/(2a)
x2 = (-b+sqrt(D))/(2a)

Answer 9

the thing is though.. I have to sketch a graph.. how would I sketch those x's?

Answer 10

parabola that opens up

Answer 11

well yeah, but the x values, I have to designate a coordinate within as close proximity as possible..