a car of mass 1000kg travelling along a straight horizontal road accelerates uniformly from 15m/s to 25m/s in a distance of 320m. if the resistance to motion is 145N, find the driving force of the engine.

Question

anonymous · Answer

Wrong section for the question.

anonymous · Answer

that is really a mathematics question.
question from chapter mechanics that I had learnt in foundation mathematics II.

anonymous · Answer

I'm sorry man maybe I am mistaken. But you do need some formulae related to Physics here..

anonymous · Answer

its ok....
so do you know how to solve that problem

cwrw238 · Answer

you use newtons 2nd law of motion
Force = mass * acceleration

cwrw238 · Answer

resultant force = driving force D - resisting force 145 N
acceleration: speed is increased from 15 to 25 over 320 using thr formula
v^2 = u^2 + 2as
25^2 = 15^2 + 640a
a  =  625 - 225  /640   =  400/640 = 5/8 m s^-2
using newtons law
D - 145 = 1000 x  5/8 =  625
D =  770 N

driving force = 770 N

anonymous · Answer

tq....

anonymous · Answer

@Cwrw: Beauty and the Brains. That's your title! 
Good one :)