Ask your own question, for FREE!
Mathematics 16 Online
OpenStudy (anonymous):

Does this series diverge or converge? ∑[(n=1),∞,(n)/(e^n )]

OpenStudy (anonymous):

converge for sure

OpenStudy (anonymous):

How can you tell? I mean, what test can be used to prove it? I've already tried the limit comparison test and direct comparison test but they don't seem to work.

OpenStudy (anonymous):

in fact it is rather small

OpenStudy (anonymous):

n<e^n so converges

OpenStudy (anonymous):

well i can tell with my eyeballs because n is a polynomial of degree 1 and e^n grows way faster than any polynomial but that doensn't help with your proof i suppose

OpenStudy (anonymous):

Oh right. This is a geometric series isn't it?

OpenStudy (anonymous):

you can use the ratio test if you like

OpenStudy (anonymous):

no it is not geometric

OpenStudy (anonymous):

Unfortunately, the lesson I'm currently doing hasn't covered it yet.

OpenStudy (anonymous):

hmm

OpenStudy (anonymous):

so only comparison test?

OpenStudy (anonymous):

zarkon, snappy way with comparison test?

OpenStudy (anonymous):

Well, I suppose I could just write the answer verbally.... As of now, we've learned the integral test, basic comparison, and limit comparison. Yeah.

OpenStudy (zarkon):

you can use the limit comparison with 1/n^2 though the ratio trest is the best(as you already noted)

OpenStudy (zarkon):

then use l'hospitals rule

OpenStudy (zarkon):

a few times

OpenStudy (anonymous):

oh well if you have integral test, it is an easy enough integral

OpenStudy (anonymous):

Oh, alright then. Thank you both very much!

OpenStudy (anonymous):

kinda odd to have to resort to an integral when a ratio would do, but what do i know?

OpenStudy (zarkon):

you know the taylor expansion of e^x?

OpenStudy (anonymous):

integration by parts vs laws of exponents...

OpenStudy (anonymous):

nope

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!