If 0 ≤ x ≤ 5 and -5 ≤ y ≤ 0, what is the minimum value of 12/|x-y|. Please explain and give answer. I would be so thankful.

Question

If 0 ≤ x ≤  5 and -5 ≤ y ≤ 0, what is the minimum value of 12/|x-y|. Please explain and give answer. I would be so thankful.

anonymous · Answer

ok fine. put x = 5 and y = -5 and see what you get

anonymous · Answer

alright thanks i will try that.

anonymous · Answer

that will be the biggest 
$$|x-y|$$ will be and therefore the smallest 
$$\frac{12}{|x-y|}$$ will be

anonymous · Answer

So the answer would be 1.2

anonymous · Answer

that is what i get.  recall that 
$$|x-y|$$ is the distance between x and y

anonymous · Answer

and if y is between -5 and 0, and x is between 0 and 5, the farthest apart they can be is if x is at 5 and y is at -5

anonymous · Answer

as for an explanation, that is the best one i have

anonymous · Answer

ok thanks i appreciate it!

anonymous · Answer

yw