Question

If 0 ≤ x ≤ 5 and -5 ≤ y ≤ 0, what is the minimum value of 12/|x-y|. Please explain and give answer. I would be so thankful.

Answer 1

ok fine. put x = 5 and y = -5 and see what you get

Answer 2

alright thanks i will try that.

Answer 3

that will be the biggest
\[|x-y|\] will be and therefore the smallest
\[\frac{12}{|x-y|}\] will be

Answer 4

So the answer would be 1.2

Answer 5

that is what i get. recall that
\[|x-y|\] is the distance between x and y

Answer 6

and if y is between -5 and 0, and x is between 0 and 5, the farthest apart they can be is if x is at 5 and y is at -5

Answer 7

as for an explanation, that is the best one i have

Answer 8

ok thanks i appreciate it!

Answer 9

yw