Which of the following is a polynomial with roots -4, -2i, and 2i ? A.x^3 - 4x^2 + 4x - 16 B.x^3 + 4x^2 + 4x + 16 C.x^3 + 2x^2 + 4x + 8 D.x^3 - 2x^2 + 4x - 8
(x+4)(x+2i)(x-2i) (x+4)(x^2-4) (x^3-4x+4x^2-16) Second one
Are you understanding the answers given? You keep asking similar questions. >.>
Its the first one. Funinabox has the right process, just said the wrong one.
yes just put the roots into factored form and distribute out x= -4, 4, 2 is.... (x+4)(x-4)(x-2) zeroes of the function, represented as polynmoial, factors, x =, whatev
what do you mean i have the right process, but said the wrong one?
show your work then
You have the right answer, but said the second one was correct
From the listed answer choices, the answer is the first one, not the second one.
how so? i actually had a mistake in my work, it should be this i believe: (x+4)(x+2i)(x-2i) (x+4)(x^2+4) (x^3-4x+4x^2+16) (x^3+4x^2-4x+16) Second choice..
Well, the only way we can settle this is with a gentleman's duel. Set your pistols, ten paces apart, then let God judge who stands.
im down with that
In other words, it doesn't matter. >.> The method is there, that's all the answer the OP needs.
until she asks the exact same question in another topic
In which case we pretend we don't notice anyways, because she's been asking virtually the same questions. Complex and real roots.
lololololo
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