Ask your own question, for FREE!
Mathematics 20 Online
OpenStudy (anonymous):

Which of the following is a polynomial with roots -4, -2i, and 2i ? A.x^3 - 4x^2 + 4x - 16 B.x^3 + 4x^2 + 4x + 16 C.x^3 + 2x^2 + 4x + 8 D.x^3 - 2x^2 + 4x - 8

OpenStudy (anonymous):

(x+4)(x+2i)(x-2i) (x+4)(x^2-4) (x^3-4x+4x^2-16) Second one

OpenStudy (anonymous):

Are you understanding the answers given? You keep asking similar questions. >.>

OpenStudy (anonymous):

Its the first one. Funinabox has the right process, just said the wrong one.

OpenStudy (anonymous):

yes just put the roots into factored form and distribute out x= -4, 4, 2 is.... (x+4)(x-4)(x-2) zeroes of the function, represented as polynmoial, factors, x =, whatev

OpenStudy (anonymous):

what do you mean i have the right process, but said the wrong one?

OpenStudy (anonymous):

show your work then

OpenStudy (anonymous):

You have the right answer, but said the second one was correct

OpenStudy (anonymous):

From the listed answer choices, the answer is the first one, not the second one.

OpenStudy (anonymous):

how so? i actually had a mistake in my work, it should be this i believe: (x+4)(x+2i)(x-2i) (x+4)(x^2+4) (x^3-4x+4x^2+16) (x^3+4x^2-4x+16) Second choice..

OpenStudy (anonymous):

Well, the only way we can settle this is with a gentleman's duel. Set your pistols, ten paces apart, then let God judge who stands.

OpenStudy (anonymous):

im down with that

OpenStudy (anonymous):

In other words, it doesn't matter. >.> The method is there, that's all the answer the OP needs.

OpenStudy (anonymous):

until she asks the exact same question in another topic

OpenStudy (anonymous):

In which case we pretend we don't notice anyways, because she's been asking virtually the same questions. Complex and real roots.

OpenStudy (anonymous):

lololololo

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!