Question

Suppose f(x) = x^2 - 3 x - 1
I found that the parabola and has 2 x intercepts but I cant find them. so can anyone help?
and the minimum is?

Answer 1

You would have to use the quadratic formula to find the intercepts.

The minimum is the point (-b/(2a), f(-b/2a))

Answer 2

can you tell meaning direct me to how to find the max for the problem i asked for before bcause I dont know how

Answer 3

is it still (-b/(2a), f(-b/2a)) equation

Answer 4

?

Answer 5

For a quadratic, yes. That point will be a minimum if the parabola opens up, and a max if it opens down.

Answer 6

for some reason I got 3/2 and its wrong for the min.

Answer 7

For anything of higher degree, you'll need to know a little calculus.

Answer 8

That's the x value of the min, You have to plug it back into the function to get the actual min.

Answer 9

oh ok for x

Answer 10

-13/4

Answer 11

and the same for the max?