A computer center has three printers: A, B, and C. Programs are routed to the first available printer. The printers print at different speeds and the probability that a program is routed to printers A, B, and C are equal to 0.5, 0.3, and 0.2, respectively. Occasionally, printers A, B, and C, jam and destroy printouts with the probabilities 0.04, 0.05, and 0.03, respectively. Your program is destroyed when a printer jams.

What is the probability that printer A is involved given that there is a jam?

Give your answer to 4 decimal places

Question

A computer center has three printers: A, B, and C. Programs are routed to the first available printer. The printers print at different speeds and the probability that a program is routed to printers A, B, and C are equal to 0.5, 0.3, and 0.2, respectively. Occasionally, printers A, B, and C, jam and destroy printouts with the probabilities 0.04, 0.05, and 0.03, respectively. Your program is destroyed when a printer jams.

What is the probability that printer A is involved given that there is a jam?

Give your answer to 4 decimal places

anonymous · Answer

P(Printer A involved given there is a jam) , (i assume involve meaning that it is involve in being jammed) 

P(Printer A involved given there is a jam)= P( A jamming) / P( A or B or C jamming)

(0.5 * 0.04) / (0.5*0.04 + 0.3*0.05 + 0.2*0.03) 
= 0.4878