Question

A 200 g particle gains a momentum of 25 Ns in 12 s starting from rest. Find the
kinetic energy of the particle and the applied force.

Answer 1

p=mv
then calculate the kinetic energy by
KE=1/2mv^2

Answer 2

i will try that solution

Answer 3

Let's use the principles of impulse and newton's second law. Impulse is defined as\[I = \int\limits F dt = F \Delta t\]Newton's second law is defined as\[F = {dp \over dt} = {\Delta p \over \Delta t}\]Therefore, if we combine the two, we can obtain the following expression\[F \Delta t = m \Delta v\]