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OpenStudy (anonymous):
*max value of...
OpenStudy (anonymous):
take its derivative and you get -12x+7=0 and x=-7/12 plug this into equation
OpenStudy (bahrom7893):
-12x+7=0
-12x=-7
x=7/12, plug that into original
OpenStudy (anonymous):
9-7*7/12-6*49/144
OpenStudy (bahrom7893):
it's positive 7/12
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OpenStudy (anonymous):
sorry x=7/12
OpenStudy (bahrom7893):
yea
OpenStudy (anonymous):
if you don't know what a derivative is, find the vertex
OpenStudy (anonymous):
first coordinate of the vertex is
\[-\frac{b}{2a}\] second coordinate is what you get when you replace x by that value, and that will be your maximum
OpenStudy (anonymous):
in fact, this is the method i would use irrespective of whether you know calculus or not
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OpenStudy (anonymous):
could you complete the square please?
OpenStudy (anonymous):
sure
OpenStudy (anonymous):
since
\[-\frac{b}{2a}=\frac{7}{12}\] and since the second coordinate is
\[\frac{265}{24}\] when you complete the square you will get
\[-6(x-\frac{7}{12})^2+\frac{265}{24}\]
OpenStudy (anonymous):
this is by far the easiest way to complete a square when the leading coefficient it not 1
OpenStudy (anonymous):
thanks a lot satellite
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