Question

i need help with the picture im going to attach in the reply area

Answer 1

if you click on the picture you ca see it clearly

Answer 2

Do you know the distance formula?

Answer 3

no

Answer 4

\[d=\sqrt{(x2-x1)^2+(y2-y1)^2}\]

Answer 5

ok can u help me solve this problem

Answer 6

so i would have x2 and x and x1 as 0 because of the origin right?

Answer 7

One of the x values will be 0 and one of the y values will be 0.

Answer 8

\[d=\sqrt{x^2+y^2}\]

Answer 9

They tell you that y=x^2-8

Answer 10

So to get the entire function in terms of x, what do you think you should do?

Answer 11

plug that in for y?

Answer 12

yes

Answer 13

\[d=\sqrt{x^2+(x^2-8)^2}\]

Answer 14

Can you simplify that by expanding?

Answer 15

x^2+x^4-16x^2+64?

Answer 16

yes, combine like terms now

Answer 17

x^4-15x^2+64

Answer 18

dont forget the square root

Answer 19

ok that whole equation is under the square root right

Answer 20

yes

Answer 21

Now what is d if x=0?

Answer 22

8?

Answer 23

yep

Answer 24

7.07? if x=1

Answer 25

the last part d is where im stuck would it be if x =1?

Answer 26

If x=1

Answer 27

\[d=\sqrt{1-15+64}=\sqrt{50}=\sqrt{25*2}=\sqrt{25}*\sqrt{2}=5\sqrt{2}\]

Answer 28

That's approximately 7.07, but if they want exact answers, use 5sqrt(2)

Answer 29

ok yea they want the approx

Answer 30

And you can use a graphing utility on your own, right?

Answer 31

idk how to use that or where to get it

Answer 32

Do you have a graphing calculator?

Answer 33

no not with me right now

Answer 34

http://www.wolframalpha.com/input/?i=sqrt%28x%5E4-15x%5E2%2B64%29+minimum+value

Answer 35

Remember, they want the positive x-value

Answer 36

Did you check the link?

Answer 37

its not coming up

Answer 38

Type this into the box at http:\\www.wolframalpha.com
minimize sqrt(x^4-15x^2+64)

Answer 39

ok great i got it thank you can u help with my other problem i posted