Question

How do i find the Y intercept of

1/(0-3)^2 + 2

Answer 1

There's no function. The constant you gave, 1/9+2, or 19/9.

Answer 2

how did you get the answer though? i have a ton of this problems to do but i want to learn the right way to do it :( soooo confused

Answer 3

You gave me a constant with no context. It's like me asking, "What's the y-intercept of 4?" There's no answer to that question.

Answer 4

oh k well this was the full question. I only asked a part of it.

Use transformations y= 1/x or y = 1/x^2 to sketch the rational function

label all intercepts and asymptotes

its asked to graph ( which i can do )

then it asks what is the Y - intercept

f(x) = 1/(x-3)^2 + 2

Answer 5

You made a typo in the original question; you put in 0 instead of x.

Which, ironically, was what you are supposed to do. The y-intercept is at the y-axis, which is when x=0.

Answer 6

i meant to do that ;) so for this equation would i do this...

3^2*2+1 = 19

3^2 = 9

so 19/9?

Answer 7

f(x) = 1/(x-3)^2 + 2 was the equation, right?
f(0) = 1/(0-3)^2 + 2

Answer 8

yes

Answer 9

f(0) = 1/(0-3)^2 + 2 this is your answer. 0 in for x